(2x+3)(x-6)-2x^2+3x=30

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Solution for (2x+3)(x-6)-2x^2+3x=30 equation: 



(2x+3)(x-6)-2x^2+3x=30

We move all terms to the left:

(2x+3)(x-6)-2x^2+3x-(30)=0

We add all the numbers together, and all the variables

-2x^2+3x+(2x+3)(x-6)-30=0

We multiply parentheses ..

-2x^2+(+2x^2-12x+3x-18)+3x-30=0

We get rid of parentheses

-2x^2+2x^2-12x+3x+3x-18-30=0

We add all the numbers together, and all the variables

-6x-48=0

We move all terms containing x to the left, all other terms to the right

-6x=48

x=48/-6

x=-8

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